document.write( "Question 243101: I am having a dinner party with five fuests. I have 11 friends from which to choose as guests. \r
\n" ); document.write( "\n" ); document.write( "From how many different collections of five dinner guests can i choose if two are married to eachother and won't come seperatly?\r
\n" ); document.write( "\n" ); document.write( "From how many different collections of five dinner guests may she choose if two are divorced from eachother and refuse to come together?
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Algebra.Com's Answer #178125 by stanbon(75887)\"\" \"About 
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I am having a dinner party with five guests. I have 11 friends from which to choose as guests.
\n" ); document.write( "From how many different collections of five dinner guests can i choose if two are married to each other and won't come seperatly?
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\n" ); document.write( "Treat those two married persons as one person.
\n" ); document.write( "# of groups of 5 will be 10C5 = 1052
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\n" ); document.write( "From how many different collections of five dinner guests may she choose if two are divorced from each other and refuse to come together?
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\n" ); document.write( "Choose one of those divorced folks: 2 ways
\n" ); document.write( "Choose 4 others to join that person: 9C4 = 126 ways
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\n" ); document.write( "Total # of groups of 5: 2*126 = 252
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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