document.write( "Question 243101: I am having a dinner party with five fuests. I have 11 friends from which to choose as guests. \r
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document.write( "From how many different collections of five dinner guests can i choose if two are married to eachother and won't come seperatly?\r
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document.write( "From how many different collections of five dinner guests may she choose if two are divorced from eachother and refuse to come together? \n" );
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Algebra.Com's Answer #178125 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I am having a dinner party with five guests. I have 11 friends from which to choose as guests. \n" ); document.write( "From how many different collections of five dinner guests can i choose if two are married to each other and won't come seperatly? \n" ); document.write( "--- \n" ); document.write( "Treat those two married persons as one person. \n" ); document.write( "# of groups of 5 will be 10C5 = 1052 \n" ); document.write( "-------------------------------------------- \n" ); document.write( "From how many different collections of five dinner guests may she choose if two are divorced from each other and refuse to come together? \n" ); document.write( "------------------------- \n" ); document.write( "Choose one of those divorced folks: 2 ways \n" ); document.write( "Choose 4 others to join that person: 9C4 = 126 ways \n" ); document.write( "--------------------------- \n" ); document.write( "Total # of groups of 5: 2*126 = 252 \n" ); document.write( "======================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |