document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243075>Question 243075</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 15 cm less than the length. The perimeter is 98 cm. Find the<BR>\n" );
document.write( "rectangle´s dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178111 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle = 2L + 2W = 98.<BR>\n" );
document.write( "W is 15 less than L, or L - 15 = W, or W + 15 = L<BR>\n" );
document.write( "Substituting from Eq 2 back into Eq 1,<BR>\n" );
document.write( "2(W+15) + 2W = 98<BR>\n" );
document.write( "2W + 30 + 2W = 98<BR>\n" );
document.write( "4W + 30 = 98<BR>\n" );
document.write( "4W = 68<BR>\n" );
document.write( "W = 17<BR>\n" );
document.write( "Recalling L = W+15<BR>\n" );
document.write( "L = 17 + 15 = 32<BR>\n" );
document.write( "Now to check our solution<BR>\n" );
document.write( "Does the perimeter = 98?<BR>\n" );
document.write( "2(32) + 2(17) = ??<BR>\n" );
document.write( "64 + 34 = 98<BR>\n" );
document.write( "Done! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );