document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243086>Question 243086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need some help with this problem:\r<BR>\n" );
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document.write( "6/z = 9/z - 1/11\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178107 by </B><A HREF=/tutors/aboutme.mpl?userid=freekie11><B>freekie11(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=freekie11><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=freekie11><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6/z=9/z-1/11\r<BR>\n" );
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document.write( "Group like terms together as:\r<BR>\n" );
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document.write( "6/z-9/z = -1/11\r<BR>\n" );
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document.write( "Look for the LCF of the equation on the left. In this case, the LCF is Z. So you will factorise as:\r<BR>\n" );
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document.write( "6-9/z = -1/11\r<BR>\n" );
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document.write( "-3/Z = -1/11\r<BR>\n" );
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document.write( "Use cross multiplication technique to eliminate the fraction.\r<BR>\n" );
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document.write( "-3 (11) = Z (-1)\r<BR>\n" );
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document.write( "-33 = -Z\r<BR>\n" );
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document.write( "Divide both sides by the negative sign or by -1\r<BR>\n" );
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document.write( "-33/-1 = -Z/-1\r<BR>\n" );
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document.write( "and the final answer will be:\r<BR>\n" );
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document.write( "Z = 33\r<BR>\n" );
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document.write( "For further clarification, contact me for free consultation on freekie11@yahoo.com </SPAN>\n" );
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