document.write( "Question 243093: I need help setting up this problem. Thanks\r
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document.write( "Red cards are worth 3 credits, while blue cards are worth 5 credits. You need any combination of 20 cards to play a game.\r
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document.write( "With 84 credits to buy cards , how many of each type of card will you have when you play? \n" );
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Algebra.Com's Answer #178104 by oberobic(2304) ![]() You can put this solution on YOUR website! Let: \n" ); document.write( "r = number of red cards \n" ); document.write( "b = number of blue cards \n" ); document.write( "We are told there are 20 cards, so: \n" ); document.write( "r + b = 20 \n" ); document.write( "which can be rearranged as: \n" ); document.write( "b=20-r \n" ); document.write( "... \n" ); document.write( "Since each r has a value of 3 and each b has a value of 5, we can compute the total. \n" ); document.write( "3r + 5b = 84 \n" ); document.write( "... \n" ); document.write( "Substituting, \n" ); document.write( "3(20-b) + 5b = 84 \n" ); document.write( "60 -3b +5b = 84 \n" ); document.write( "2b=24 \n" ); document.write( "b=12 \n" ); document.write( "Since the total number of cards is 20, then \n" ); document.write( "r=8 \n" ); document.write( "Checking the answer... \n" ); document.write( "3r = 24 \n" ); document.write( "5b = 60 \n" ); document.write( "24+60=84 \n" ); document.write( " |