document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243087>Question 243087</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I just need help setting this up. \r<BR>\n" );
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document.write( "A chemist has one solution that is 20% saline and a second that is 65% saline. The chemist makes 120 gallons of a solution that is 50% saline by combining the two solutions.  \r<BR>\n" );
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document.write( "How much of each solution is used in the mixture?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178102 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that is 20% saline and a second that is 65% saline. The chemist makes 120 gallons of a solution that is 50% saline by combining the two solutions. <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "saline + saline = saline<BR>\n" );
document.write( "0.20x + 0.65(120-x) = 0.50*120<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "20x + 65*120 - 65x = 50*120<BR>\n" );
document.write( "-45x = -15*120<BR>\n" );
document.write( "x = (1/3)120<BR>\n" );
document.write( "x = 40 gallons (amt. of 20% solution needed in the mixture)<BR>\n" );
document.write( "120-x = 120-40 = 80 gallons (amt. of 65% solution needed in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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