document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243080>Question 243080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me sove the folloiwng problem\r<BR>\n" );
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document.write( "If log2=.3010 and log3=.4771, find the value of x when 3^(x+3)=135. DO NOT use tables or calculators. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #178092 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=178092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If log2=.3010 and log3=.4771, find the value of x when 3^(x+3)=135. <BR>\n" );
document.write( "DO NOT use tables or calculators.<BR>\n" );
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document.write( "3^(x+3) = 135<BR>\n" );
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document.write( "Change the form of 135<BR>\n" );
document.write( "3^(x+3) = 3^ 5<BR>\n" );
document.write( "x+3 = 5<BR>\n" );
document.write( "x = 2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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