document.write( "Question 243041: on a test of 80 items, pedro got 93% correct. (there was partial credit on some items.) how many items did he get correct?incorrect? \n" ); document.write( "
Algebra.Com's Answer #178084 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! The percent correct is the number correct divided by the total number of items. \n" ); document.write( "If there were 100 questions, then 93/100 would yield 93% correct. \n" ); document.write( "But instead of 100 we have only 80 questions. \n" ); document.write( "Since we want the number correct, 'x', to be 93% of 80, we can setup the equation as: \n" ); document.write( "x/80 = 93/100 \n" ); document.write( "Multiply both sides by 80 \n" ); document.write( "x = 80(93/100) = (80*93)/100 = 7440/100 = 74.40 \n" ); document.write( "So Pedro got 74 and 4/10 questions correct. \n" ); document.write( "... \n" ); document.write( "Another way to get there is to just multiply 80 * .93 = 74.40 \n" ); document.write( " |