document.write( "Question 242521: A boat goes 15 miles downstream. The return trip upstream takes 40 minutes longer. The boat can travel 12 miles per hour in still water. What is the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #178082 by ankor@dixie-net.com(22740)\"\" \"About 
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A boat goes 15 miles downstream. The return trip upstream takes 40 minutes longer.
\n" ); document.write( " The boat can travel 12 miles per hour in still water.
\n" ); document.write( " What is the speed of the current?
\n" ); document.write( ":
\n" ); document.write( "let c = speed of the current
\n" ); document.write( "then
\n" ); document.write( "(12-c) = speed upstream
\n" ); document.write( "and
\n" ); document.write( "(12+c) = speed down stream
\n" ); document.write( ":
\n" ); document.write( "Change 40 min to \"2%2F3\" hr
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Time upstream - time down stream = 40 min
\n" ); document.write( "\"15%2F%28%2812-c%29%29\" - \"15%2F%28%2812%2Bc%29%29\" = \"2%2F3\"
\n" ); document.write( "Multiply equation by 3(12+c)(12-c); results
\n" ); document.write( ":
\n" ); document.write( "3(12+c)*15 - 3(12-c)*15 = 2(12-c)(12+c)
\n" ); document.write( ":
\n" ); document.write( "45(12+c) - 45(12-c) = 2(144 - c^2)
\n" ); document.write( ":
\n" ); document.write( "540 + 45c - 540 + 45c = 288 - 2c^2
\n" ); document.write( "Group like terms on the left
\n" ); document.write( "2c^2 + 45c + 45c + 540 - 540 - 288 = 0
\n" ); document.write( "which is
\n" ); document.write( "2c^2 + 90c - 288 = 0
\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "c^2 + 45c - 144 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(c+48)(c-3) = 0
\n" ); document.write( "positive solution
\n" ); document.write( "c = 3 mph is the current
\n" ); document.write( ":
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\n" ); document.write( "Check solution:
\n" ); document.write( "15/9 - 15/15 =
\n" ); document.write( "5/3 - 3/3 = 2/3
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