document.write( "Question 243047: The perimeter of a rectangle is 16 times the width. THe length us 12cm more than the width. WHat is the length and width of the rectangle? I can't figure out the formula to solve the problem. \n" ); document.write( "
Algebra.Com's Answer #178054 by oberobic(2304)\"\" \"About 
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We know the perimeter of a rectangle = P = 2W + 2L, where W=width and L=length.
\n" ); document.write( "...
\n" ); document.write( "We are told P = 16W, so 16W = 2W + 2L.
\n" ); document.write( "Subtracting 2W from both sides:
\n" ); document.write( "14W = 2L
\n" ); document.write( "Dividing by 2:
\n" ); document.write( "7W = L
\n" ); document.write( "...
\n" ); document.write( "We are told L-12=W.
\n" ); document.write( "Substituting for L, we have
\n" ); document.write( "7W-12 = W
\n" ); document.write( "Adding 12 to both sides
\n" ); document.write( "7W = W + 12
\n" ); document.write( "Subtracting W from both sides
\n" ); document.write( "6W = 12
\n" ); document.write( "Dividing by 6
\n" ); document.write( "W = 2
\n" ); document.write( "...
\n" ); document.write( "Since L is 12 more than W (given), we have
\n" ); document.write( "L = W + 12 = 2 + 12 = 14
\n" ); document.write( "L = 14
\n" ); document.write( "...
\n" ); document.write( "To check our work, let's substitute back into the givens.
\n" ); document.write( "P = 2(2) + 2(14) = 4 + 28 = 32.
\n" ); document.write( "Is 32 = 16W? Yes it is.
\n" ); document.write( "Done. \n" ); document.write( "
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