document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31106>Question 31106</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0201797127/algebrahomeworkh>Introductory Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Three consecutive intergers are such that the first plus one-half the second plus seven less than twice the third is 2101. What are the integers? Help!!! </SPAN>\n" );
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document.write( "LET THE 3 CONSEUTIVE INTEGERS BE X,X+1,X+2<BR>\n" );
document.write( "FIRST NUMBER =X................................1<BR>\n" );
document.write( "HALF OF SECOND NUMBER =(X+1)/2...............2<BR>\n" );
document.write( "TWICE THE THIRD =2(X+2)=2X+4<BR>\n" );
document.write( "SEVEN LESS THAN THIS =2X+4-7=2X-3...........3<BR>\n" );
document.write( "SUM OF THESE 3 IS <BR>\n" );
document.write( "X+(X+1)/2 +2X-3=2101.....MULTIPLY BY 2 THROUGH OUT<BR>\n" );
document.write( "2X+X+1+4X-6=4202<BR>\n" );
document.write( "7X=4202-1+6=4207<BR>\n" );
document.write( "X=4207/7=601<BR>\n" );
document.write( "SO THE INTEGERS ARE X=601,X+1=602,X+2=603. </SPAN>\n" );
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