document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242967>Question 242967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The denominator of a fraction is one less than twice the numerator. If seven is added to both the numerator and the denominator, the resulting fraction has a value of seven-tenths. Find the original fraction.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177995 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The denominator of a fraction is one less than twice the numerator. If seven is added to both the numerator and the denominator, the resulting fraction has a value of seven-tenths. Find the original fraction. <BR>\n" );
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document.write( "Let the numerator be \"x\".<BR>\n" );
document.write( "The the denominator is \"2x-1\".<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "(x+7/(2x-1+7) = 7/10<BR>\n" );
document.write( "Cross multiply to get:<BR>\n" );
document.write( "10(x+7) = 7(2x+6)<BR>\n" );
document.write( "10x + 70 = 14x+42<BR>\n" );
document.write( "4x = 28<BR>\n" );
document.write( "x = 7<BR>\n" );
document.write( "2x-1 = 13<BR>\n" );
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document.write( "The original fraction is 7/13<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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