document.write( "Question 242901: please help me solve the problem log(b^2)(x)+log(x^2)b=1, b>0, b not equal to 1, x not equal to 1. Sove for x. Please note b^2 and x^2 are subscripts (bases).
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Algebra.Com's Answer #177967 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"log%28b%5E2%2C%28x%29%29%2Blog%28x%5E2%2C%28b%29%29=1\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( " Use the change of base formula.\r
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\n" ); document.write( "\n" ); document.write( " Pull down the exponents using the identity \"log%28b%2C%28x%5Ey%29%29=y%2Alog%28b%2C%28x%29%29\"\r
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\n" ); document.write( "\n" ); document.write( " Pull out the constants.\r
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\n" ); document.write( "\n" ); document.write( " Factor out the GCF \"1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( " Multiply both sides by 2.\r
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\n" ); document.write( "\n" ); document.write( "Now let \"z=log%2810%2C%28x%29%29%2Flog%2810%2C%28b%29%29\". Take note that . In other words, \"1%2Fz=log%2810%2C%28b%29%29%2Flog%2810%2C%28x%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"z%2B1%2Fz=2\" Make the proper substitutions.\r
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\n" ); document.write( "\n" ); document.write( "\"z%5E2%2B1=2z\" Multiply EVERY term by the LCD 'z' to clear out the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"z%5E2-2z%2B1=0\" Subtract 2z from both sides.\r
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\n" ); document.write( "\n" ); document.write( "Notice that the quadratic \"z%5E2-2z%2B1\" is in the form of \"Az%5E2%2BBz%2BC\" where \"A=1\", \"B=-2\", and \"C=1\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for \"z\":\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%28-%28-2%29+%2B-+sqrt%28+%28-2%29%5E2-4%281%29%281%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=-2\", and \"C=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%282+%2B-+sqrt%28+%28-2%29%5E2-4%281%29%281%29+%29%29%2F%282%281%29%29\" Negate \"-2\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%282+%2B-+sqrt%28+4-4%281%29%281%29+%29%29%2F%282%281%29%29\" Square \"-2\" to get \"4\". \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%282+%2B-+sqrt%28+4-4+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%281%29\" to get \"4\"\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%282+%2B-+sqrt%28+0+%29%29%2F%282%281%29%29\" Subtract \"4\" from \"4\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%282+%2B-+sqrt%28+0+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%282+%2B-+0%29%2F%282%29\" Take the square root of \"0\" to get \"0\". \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%282+%2B+0%29%2F%282%29\" or \"z+=+%282+-+0%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+%282%29%2F%282%29\" or \"z+=++%282%29%2F%282%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"z+=+1\" or \"z+=+1\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the only solution in terms of z is \"z+=+1\" \r
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\n" ); document.write( "\n" ); document.write( "But remember, we let \"z=log%2810%2C%28x%29%29%2Flog%2810%2C%28b%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"z=log%2810%2C%28x%29%29%2Flog%2810%2C%28b%29%29\" Go back to that previous equation.\r
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\n" ); document.write( "\n" ); document.write( "\"1=log%2810%2C%28x%29%29%2Flog%2810%2C%28b%29%29\" Plug in \"z+=+1\" \r
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\n" ); document.write( "\n" ); document.write( "\"log%2810%2C%28b%29%29=log%2810%2C%28x%29%29\" Multiply both sides by \"log%2810%2C%28b%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"b=x\" Since the bases are equal, the arguments are equal.\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=b\"\r
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