document.write( "Question 242519: the largest 3 consecutive integers for which the first is increased by twice the second exceeds the third by less than 25. (have to solve algrebraically)\r
\n" ); document.write( "\n" ); document.write( "I do not know how to put \"exceeds\" in an equation.\r
\n" ); document.write( "\n" ); document.write( "Please give me the answer and a detailed explanation of it!
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Algebra.Com's Answer #177961 by MathTherapy(10559)\"\" \"About 
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the largest 3 consecutive integers for which the first is increased by twice the second exceeds the third by less than 25. (have to solve algrebraically)\r
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\n" ); document.write( "\n" ); document.write( "Let the 1st of the 3 consecutive integer be F\r
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\n" ); document.write( "\n" ); document.write( "Then the 2nd and 3rd integers are F + 1, and F + 2, respectively\r
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\n" ); document.write( "\n" ); document.write( "Increasing the 1st by twice the second gives us F + 2(F + 1). Since this result exceeds the third by less than 25, it means that F + 2(F + 1) is greater than the 3rd integer, and when the 3rd integer, or F + 2 is subtracted from F + 2(F + 1), we should get a number that is less than 25. Therefore, putting this in mathematical terminology, we get:\r
\n" ); document.write( "\n" ); document.write( "F + 2(F + 1) - (F + 2) < 25\r
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\n" ); document.write( "\n" ); document.write( "F + 2F + 2 - F - 2 < 25\r
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\n" ); document.write( "\n" ); document.write( "2F < 25\r
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\n" ); document.write( "\n" ); document.write( "Therefore, F, or the 1st number < \"25%2F2\", or < 12.5\r
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\n" ); document.write( "\n" ); document.write( "Since we're talking about INTEGERS, then the integer that is less than 12.5 is 12. Therefore, with F, or the 1st integer being 12, the 3 INTEGERS are \"highlight_green%2812_13_and_14%29\".
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