document.write( "Question 31098This question is from textbook Prealgebra and Introductory Algebra
\n" ); document.write( ": A runner begins her workout by jogging to the park, a distance of 3 miles. She then jogs home at the same speed but along a different route. This return trip is 9 miles and he time is one hour longer. Complete the accompany chart abd use it to find the runner jogging speed. t=d\t \n" ); document.write( "
Algebra.Com's Answer #17795 by Paul(988)\"\" \"About 
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Let the speed be x
\n" ); document.write( "\"3%2Fx-9%2Fx=1\"
\n" ); document.write( "9x-3x=(x)(x)
\n" ); document.write( "\"6x=x%5E2\"
\n" ); document.write( "\"x%5E2-6x=0\"
\n" ); document.write( "Factor left side:
\n" ); document.write( "x(x-6)=0
\n" ); document.write( "x=0 or x=6
\n" ); document.write( "hence, the jogging speed is 6mph.
\n" ); document.write( "Paul.
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