document.write( "Question 31098This question is from textbook Prealgebra and Introductory Algebra
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document.write( ": A runner begins her workout by jogging to the park, a distance of 3 miles. She then jogs home at the same speed but along a different route. This return trip is 9 miles and he time is one hour longer. Complete the accompany chart abd use it to find the runner jogging speed. t=d\t \n" );
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Algebra.Com's Answer #17795 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let the speed be x \n" ); document.write( " \n" ); document.write( "9x-3x=(x)(x) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Factor left side: \n" ); document.write( "x(x-6)=0 \n" ); document.write( "x=0 or x=6 \n" ); document.write( "hence, the jogging speed is 6mph. \n" ); document.write( "Paul. \n" ); document.write( " |