document.write( "Question 242623: A rectangle has a length 2 meters less than twice its width. When 5 meters is added to the width, the result is a square with an area of 144 square meters. Find the dimensions of the original rectangle
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Algebra.Com's Answer #177899 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W-2 \n" ); document.write( "(2W-2)(W+5)=144 \n" ); document.write( "2W^2-2W+10W-10=144 \n" ); document.write( "2W^2+8W-10-144=0 \n" ); document.write( "2W^2+8W-154=0 \n" ); document.write( "2(W^2+4W-77)=0 \n" ); document.write( "2(W+11)(W-7)=0 \n" ); document.write( "W-7=0 \n" ); document.write( "W=7 ANS FOR THE ORIGINAL WIDTH. \n" ); document.write( "7+7=12 IS THE EXPANDED WIDTH. \n" ); document.write( "L=2*7-2 \n" ); document.write( "L=14-2=12 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "12*12=144 \n" ); document.write( "144=144\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |