document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242898>Question 242898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please show me how to divide by long division this: (3x^3+4x-1) / (x^2+1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177871 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Good morning, <BR>\n" );
document.write( "When dividing polynomials, it is set up like simple division problems. Let's look at x^2+1 and see what we'd have to multiply to make it 3x^2 + 4x<BR>\n" );
document.write( "As you can see, we'd have to multiply it by 3x. That would give us 3x^3 +3x right?<BR>\n" );
document.write( "so subtract 3x^3+3x from 3x^3+4x leaves us with x. now bring down the -1 to make it x-1. Notice x^2 + 1 doesn't go into x-1 so the answer is: <BR>\n" );
document.write( "3x+0 remainder x-1<BR>\n" );
document.write( "(Note: I realize this might be tough to follow without showing the actual division sign)<BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com<BR>\n" );
document.write( "you can email me directly at rjpublishers@yahoo.com if you have further questions. </SPAN>\n" );
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