document.write( "Question 242897: the hypotenuse of an isosceles right triangle measures 15 feet. need to find the area? \n" ); document.write( "

Algebra.Com's Answer #177863 by unlockmath(1688) $\"\"$ $\"About$

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\n" ); document.write( "This has a couple steps so here we go. First formula we'll use is:
\n" ); document.write( "a^2 + b^2 = c^2 c is the hypotenuse and since both legs are the same size we'll show them with x. It looks like this:
\n" ); document.write( "x^2 + x^2 = 15^2 Expand this and combine like terms will give us:
\n" ); document.write( "2x^2=225 Divide both sides by 2 will be:
\n" ); document.write( "x^2=112.5 Square rood both sides will be:
\n" ); document.write( "x=10.61 (rounded off) This is the length of both sides.
\n" ); document.write( "Now, we'll use the area of a triangle which is area=1/2(base)(height) plug in the numbers:
\n" ); document.write( "area=1/2(10.61)(10.61)
\n" ); document.write( "area= 56.29 square feet (rounded off)
\n" ); document.write( "RJ Toftness
\n" ); document.write( "Check out my book at www.math-unlock.com \n" ); document.write( "

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