document.write( "Question 31075: how do I use substitution to solve the linear system for \r
\n" ); document.write( "\n" ); document.write( "X + 3/4y = 3/4\r
\n" ); document.write( "\n" ); document.write( "2y = 4x + 16
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\n" ); document.write( " by the way its not from a text book\r
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Algebra.Com's Answer #17786 by aussie7us(3)\"\" \"About 
You can put this solution on YOUR website!
Try to get the X or Y variable isolated on one side.
\n" ); document.write( "So you could do-\r
\n" ); document.write( "\n" ); document.write( "\"x=3%2F4-3%2F4y\"
\n" ); document.write( "then plug it into the other equation\r
\n" ); document.write( "\n" ); document.write( "\"2y=4%283%2F4-3%2F4y%29\"
\n" ); document.write( "distribute\r
\n" ); document.write( "\n" ); document.write( "\"2y=4-3y\"\r
\n" ); document.write( "\n" ); document.write( "add 3y to both sides
\n" ); document.write( "\"5y=4\"\r
\n" ); document.write( "\n" ); document.write( "and divide by five
\n" ); document.write( "\"y=5%2F4\"\r
\n" ); document.write( "\n" ); document.write( "Then plug it back into the first equation.\r
\n" ); document.write( "\n" ); document.write( "\"x%2B%283%2F4%29%2A%285%2F4%29=+3%2F4\"\r
\n" ); document.write( "\n" ); document.write( "multiply
\n" ); document.write( "\"x%2B15%2F16=3%2F4\"\r
\n" ); document.write( "\n" ); document.write( "subtract 15/16 from both sides
\n" ); document.write( "\"x=3%2F16\"\r
\n" ); document.write( "\n" ); document.write( "OR YOU COULD GO THE OTHER WAY AND WORK OUT X AND THEN Y. (this one showed first y and then 'plugged in' x)
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