document.write( "Question 242783: A right triangle has a perimeter of 32 and an area of 20. what is the length of the hypotenuse? \n" ); document.write( "
Algebra.Com's Answer #177825 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 1) a+b+c=32 \n" ); document.write( ". \n" ); document.write( "2) \n" ); document.write( "(a*b)/2=20 \n" ); document.write( "a*b=40 \n" ); document.write( "a=40/b \n" ); document.write( ". \n" ); document.write( "1) \n" ); document.write( "c=32-b- 40/b substitute 40/b for a. \n" ); document.write( "c=(32b-b^2-40)/b \n" ); document.write( ". \n" ); document.write( "3) \n" ); document.write( "a^2+b^2=c^2 \n" ); document.write( "(40/b)^2+b^2 \n" ); document.write( "=1600/b^2+b^2 \n" ); document.write( ". \n" ); document.write( "1600/b^2 + b^2 = ((32b-b^2-40)/b)^2 \n" ); document.write( "1600/b^2 + b^2 = b^2-64b- 2560/b + 1600/b^2+1104 \n" ); document.write( "1600+b^4=b^4-64b^3-2560b+1600+1104b^2 \n" ); document.write( "-64b^3+1104b^2-2560b=0 \n" ); document.write( "-16b(4b^2-69b+160)=0 \n" ); document.write( "4b^2-69b+160=0 \n" ); document.write( "b=2.76..., b=14.49 (both legs, actually) \n" ); document.write( "2.76^2+14.49^2=217.56 \n" ); document.write( "sqrt(217.5625)=14.75 Hypotenuse \n" ); document.write( "That was a tough one! \n" ); document.write( ". \n" ); document.write( "Ed\r \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( " |