document.write( "Question 242822: Alexander an artist, welded 3 pieces of bronze together to create a project. The second piece is one-half of the first piece. The third piece is 4 less that the first piece. The total length of the pieces is 86 inches. How long was each piece? \n" ); document.write( "
Algebra.Com's Answer #177807 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! F = length of first piece \n" ); document.write( "S = length of second piece = .5F \n" ); document.write( "T = length of third piece = F-4 \n" ); document.write( "F+S+T=86 \n" ); document.write( "Substituting what we know... \n" ); document.write( "F + .5F + (F-4) = 86 \n" ); document.write( "Combining... \n" ); document.write( "2.5F - 4 = 86 \n" ); document.write( "Adding 4 to both sides... \n" ); document.write( "2.5F = 90 \n" ); document.write( "Dividing both sides by 2.5 \n" ); document.write( "F = 36 \n" ); document.write( "Substituting back into our formulas... \n" ); document.write( "S = .5F = .5(36) = 18 \n" ); document.write( "T = F - 4 = 36 - 4 = 32 \n" ); document.write( "Check the sum... \n" ); document.write( "36 + 18 + 32 (equals?) 86? \n" ); document.write( "Yes it does. \n" ); document.write( " |