document.write( "Question 242822: Alexander an artist, welded 3 pieces of bronze together to create a project. The second piece is one-half of the first piece. The third piece is 4 less that the first piece. The total length of the pieces is 86 inches. How long was each piece? \n" ); document.write( "
Algebra.Com's Answer #177807 by oberobic(2304)\"\" \"About 
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F = length of first piece
\n" ); document.write( "S = length of second piece = .5F
\n" ); document.write( "T = length of third piece = F-4
\n" ); document.write( "F+S+T=86
\n" ); document.write( "Substituting what we know...
\n" ); document.write( "F + .5F + (F-4) = 86
\n" ); document.write( "Combining...
\n" ); document.write( "2.5F - 4 = 86
\n" ); document.write( "Adding 4 to both sides...
\n" ); document.write( "2.5F = 90
\n" ); document.write( "Dividing both sides by 2.5
\n" ); document.write( "F = 36
\n" ); document.write( "Substituting back into our formulas...
\n" ); document.write( "S = .5F = .5(36) = 18
\n" ); document.write( "T = F - 4 = 36 - 4 = 32
\n" ); document.write( "Check the sum...
\n" ); document.write( "36 + 18 + 32 (equals?) 86?
\n" ); document.write( "Yes it does.
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