document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242841>Question 242841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving this problem: solve for x: 28^x=10^(-3x) I really need to understand this. Please show and explain all steps. Thanks in advance :D </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177804 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I need help solving this problem: solve for x: 28^x=10^(-3x) I really need to understand this. Please show and explain all steps.<BR>\n" );
document.write( "--------------------------------<BR>\n" );
document.write( "28^x=10^(-3x)<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "x*log(28) = -3x<BR>\n" );
document.write( "---<BR>\n" );
document.write( "3x + x*log(28) = 0<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Factor:<BR>\n" );
document.write( "x(3+log(28)) = 0<BR>\n" );
document.write( "x = 0 <BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );