document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=241738>Question 241738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE SLOPE FORM OF THE EQUATION OF THE LINE PERPENDICULAR TO THE GRAPH OF Y = -3/2x - 7 THAT PASSES THROUGH (3,-2). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177801 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PERPENDICULAR TO THE GRAPH OF Y = -3/2x - 7 THAT PASSES THROUGH (3,-2).<BR>\n" );
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document.write( "The slope of y = (-3/2)x - 7 is -3/2.<BR>\n" );
document.write( "The slope of lines perpendicular is the negative inverse, = 2/3<BR>\n" );
document.write( "Use y = mx + b and the point to find b<BR>\n" );
document.write( "-2 = (2/3)*3 + b<BR>\n" );
document.write( "b = -4<BR>\n" );
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document.write( "y = (2/3)x - 4<BR>\n" );
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