document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242628>Question 242628</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of two consecutive odd integers is 2 less than six times their sum. Can you find the two integers.\r<BR>\n" );
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document.write( "I thought I could solve but having trouble. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177795 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Start by defining what you know.<BR>\n" );
document.write( "When working with consecutive digits, x & x+1 are the best choices for solving with one unknown.<BR>\n" );
document.write( "BUT, we are told they are consecutive ODD digits, so we'll use x & x+2.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "The sum = x + x+2 = 2x + 2 = 2(x+1)<BR>\n" );
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document.write( "The product is x * (x + 2) = x^2 + 2x<BR>\n" );
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document.write( "The product is 2 less than the 6 times the sum, so  6 times the sum = product + 2.<BR>\n" );
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document.write( "Combining what we know...<BR>\n" );
document.write( "Six times the sum:  6(2x + 2) = 12(x+1) = 12x + 12<BR>\n" );
document.write( "12x + 12 = x^2 + 2x + 2<BR>\n" );
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document.write( "Subtract (12x + 12) from both sides.<BR>\n" );
document.write( "0 = x^2 + 2x + 2 - 12x - 12<BR>\n" );
document.write( "Combining like terms.<BR>\n" );
document.write( "0 = x^2 - 10x - 10<BR>\n" );
document.write( "OR<BR>\n" );
document.write( "x^2 - 10x - 10 = 0<BR>\n" );
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document.write( "Since this does NOT factor, there are no integer solutions. </SPAN>\n" );
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