document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242810>Question 242810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of angle A is three times the measure of angle B, and the measure of angle B is three times the measure for angle C. If angle A.and angle C.are complementary, find the measure of angle B. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177780 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177780\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are told several things needed for the setup for the solution.<BR>\n" );
document.write( "A = 3 times B<BR>\n" );
document.write( "A = 3B<BR>\n" );
document.write( "B = 3 times C<BR>\n" );
document.write( "B = 3C<BR>\n" );
document.write( "Therefore, A = 9C<BR>\n" );
document.write( "A + C = 90 degrees because they are complementary.<BR>\n" );
document.write( "Substituting for A = 9C<BR>\n" );
document.write( "9C + C = 90<BR>\n" );
document.write( "10C = 90<BR>\n" );
document.write( "Dividing by 10<BR>\n" );
document.write( "C = 9<BR>\n" );
document.write( "Substituting<BR>\n" );
document.write( "A = 9C = 9(9) = 81<BR>\n" );
document.write( "But what is the question?<BR>\n" );
document.write( "What is B?<BR>\n" );
document.write( "B = 3C<BR>\n" );
document.write( "C = 9<BR>\n" );
document.write( "B = 27<BR>\n" );
document.write( "Checking our work.<BR>\n" );
document.write( "A = 3B = 3(27)??<BR>\n" );
document.write( "Yes, 3*27 = 81= A. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );