document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242805>Question 242805</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is eleven more than twice another. If their sum is decreased by nine, the result is seventeen. Find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177772 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's establish one number represented by x. The other number will be 2x+11 Then we can add these and subtract 9 to equal 17. Here's how it will look. <BR>\n" );
document.write( "[(2x+11) + x] -9 = 17 Now we can combine like terms.<BR>\n" );
document.write( "3x+2=17 Subtract 2 from both sides. <BR>\n" );
document.write( "3x=15  Divide 3 into both sides. <BR>\n" );
document.write( "x = 5<BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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