document.write( "Question 242782: how do you solve square root and the 3 outside of it but in the little root thing and then inside the root 4+6t-the 3 in the outside of the root (but on it) square root of 1-8t=0 \n" ); document.write( "
Algebra.Com's Answer #177756 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
how do you solve square root and the 3 outside of it but in the little root thing and then inside the root 4+6t-the 3 in the outside of the root (but on it) square root of 1-8t=0
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document.write( "I think this is what you are describing:\r\n" );
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document.write( "\"root%283%2C4%2B6t%29-root%283%2C1-8t%29=0\"\r\n" );
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document.write( "Add the opposite of second term to both sides:\r\n" );
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document.write( "\"root%283%2C4%2B6t%29=root%283%2C1-8t%29\"\r\n" );
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document.write( "Raise both sides to the 3 power:\r\n" );
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document.write( "\"%28root%283%2C4%2B6t%29%29%5E3=%28root%283%2C1-8t%29%29%5E3\"\r\n" );
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document.write( "When you raise a root to the same power as its index,\r\n" );
document.write( "you take away the root and the exponent and just\r\n" );
document.write( "leave what's underneath:\r\n" );
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document.write( "\"4%2B6t=1-8t\"\r\n" );
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document.write( "\"14t=-3\"\r\n" );
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document.write( "\"t=%28-3%29%2F14\"\r\n" );
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document.write( "\"t=-3%2F14\"\r\n" );
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document.write( "Edwin
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