document.write( "Question 242786: square root of p^2-3p+16 (the square root ends on top of 16)=p+1 \n" ); document.write( "
Algebra.Com's Answer #177746 by jim_thompson5910(35256)\"\" \"About 
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\"sqrt%28p%5E2-3p%2B16%29=p%2B1\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"p%5E2-3p%2B16=%28p%2B1%29%5E2\" Square both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"p%5E2-3p%2B16=p%5E2%2B2p%2B1\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"-3p%2B16=2p%2B1\" Subtract \"p%5E2\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-3p=2p%2B1-16\" Subtract \"16\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-3p-2p=1-16\" Subtract \"2p\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-5p=1-16\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-5p=-15\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"p=%28-15%29%2F%28-5%29\" Divide both sides by \"-5\" to isolate \"p\".\r
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\n" ); document.write( "\n" ); document.write( "\"p=3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"p=3\"
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