document.write( "Question 242742: A goldsmith has two alloys that are different purities of gold. The first is three-fourths pure gold and the second is five twelfths pure gold. How many ounces of each should be melted and mixed in order to obtain a 6-oz mixture that is two-thirds pure gold? \n" ); document.write( "
Algebra.Com's Answer #177725 by checkley77(12844)\"\" \"About 
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.75x+5/12(6-x)=2/3*6
\n" ); document.write( ".75x+5*6/12-5/12x=12/3
\n" ); document.write( ".75x+30/12-5x/12=4
\n" ); document.write( ".75x-5x/12+2.5=4
\n" ); document.write( "(.75x*12-5x)/12=4-2.5
\n" ); document.write( "(9x-5x)/12=1.5
\n" ); document.write( "4x=1.5*12
\n" ); document.write( "4x=18
\n" ); document.write( "x=18/4
\n" ); document.write( "x=4.5 oz. of 3/4 pure gold is used.
\n" ); document.write( "6-4.5=1.5 oz. of 5/12 pure gold is used.
\n" ); document.write( "Proof:
\n" ); document.write( ".75*4.5+5/12*1.5=2/3*6
\n" ); document.write( "3.375+.625=4
\n" ); document.write( "4=4
\n" ); document.write( "
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