document.write( "Question 242760: I sent this problem earlier but after receiving a response quickly realized I entered the wrong problem, can u please help me with this one? I have no clue where to start. Thanks in advance!!
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document.write( "Solve:\r
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document.write( "(x+2)(x-2)(x+1)>0
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document.write( "a)the solution set is
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document.write( "b)solution is all real numbers
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document.write( "c)there is no solution \n" );
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Algebra.Com's Answer #177714 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First thing to do is to solve the problem that you posted before, namely:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take the three roots of this equation, call them \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For each of the four intervals, select a value and substitute it back into the original inequality. Once you have done that, two of the values will result in true statements and two of them will make the original inequality false. The union of the two intervals from which the values that made the original inequality true is the solution set of your inequality.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |