document.write( "Question 242760: I sent this problem earlier but after receiving a response quickly realized I entered the wrong problem, can u please help me with this one? I have no clue where to start. Thanks in advance!!
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Algebra.Com's Answer #177712 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28x-2%29%28x%2B2%29%28x%2B1%29%3E0\" Start with the given inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%28x%2B2%29%28x%2B1%29=0\" Set the left side equal to zero\r
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\n" ); document.write( "\n" ); document.write( "Set each individual factor equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "\"x-2=0\", \"x%2B2=0\" or \"x%2B1=0\"\r
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\n" ); document.write( "\n" ); document.write( "Solve for x in each case:\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\", \"x=-2\" or \"x=-1\"\r
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\n" ); document.write( "\n" ); document.write( "So our critical values are \"x=2\", \"x=-2\" and \"x=-1\"\r
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\n" ); document.write( "\n" ); document.write( "Now set up a number line and plot the critical values on the number line\r
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\n" ); document.write( "\n" ); document.write( "\"number_line%28+600%2C+-10%2C+10%2C2%2C-2%2C-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So let's pick some test points that are near the critical values and evaluate them.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is less than \"-2\" (notice how it's to the left of the leftmost endpoint). This corresponds to the left most interval ()\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%28x%2B2%29%28x%2B1%29%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%28-3-2%29%28-3%2B2%29%28-3%2B1%29%3E+0\" Plug in \"x=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"-10%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is in between \"-2\" and \"-1\". This corresponds to the left middle interval ()\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=-1.5\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%28x%2B2%29%28x%2B1%29%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%28-1.5-2%29%28-1.5%2B2%29%28-1.5%2B1%29%3E+0\" Plug in \"x=-1.5\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.875%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.\r
\n" ); document.write( "\n" ); document.write( " So part our solution in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is in between \"-1\" and \"2\". This corresponds to the right middle interval ()\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%28x%2B2%29%28x%2B1%29%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%280-2%29%280%2B2%29%280%2B1%29%3E+0\" Plug in \"x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"-4%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is greater than \"2\" (notice how it's to the right of the rightmost endpoint). This corresponds to the right most interval ()\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3%2Bx%5E2-4x-4%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%283-2%29%283%2B2%29%283%2B1%29%3E+0\" Plug in \"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"20%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.\r
\n" ); document.write( "\n" ); document.write( " So part our solution in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "Summary:\r
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\n" ); document.write( "\n" ); document.write( "So the solution in interval notation is:\r
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