document.write( "Question 242690: (4/3)^-2 \n" ); document.write( "

Algebra.Com's Answer #177669 by unlockmath(1688) $\"\"$ $\"About$

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Hello,
\n" ); document.write( "First we need to get rid of the negative exponent. To do that we place it in the denominator to look like:
\n" ); document.write( "1/(4/3)^2 Now we do 4 and 3 to the second power to look like:
\n" ); document.write( "1/16/9 This can be rewritten as:
\n" ); document.write( "9/16
\n" ); document.write( "RJ Toftness
\n" ); document.write( "www.math-unlock.com \n" ); document.write( "

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