document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4024>Question 4024</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 50ft. The width of a rectangle is 5ft. less than the length. Find the length and the width of the rectangle. P = 2w +2L </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1776 by </B><A HREF=/tutors/aboutme.mpl?userid=alok><B>alok(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alok><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle= 2w+2l where w is the width & l is the length.\r<BR>\n" );
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document.write( "Here, width is length less 5 ft.\r<BR>\n" );
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document.write( "or w=l-5\r<BR>\n" );
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document.write( "hence replacing w by l-5 we get P= 2(l-5)+2l=50\r<BR>\n" );
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document.write( "or 50= 2l -10+2l <BR>\n" );
document.write( "or 50=4l-10<BR>\n" );
document.write( "or 60=4l<BR>\n" );
document.write( "or l=60/4<BR>\n" );
document.write( "or l=15\r<BR>\n" );
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document.write( "hence length is 15 ft & width is 10 ft </SPAN>\n" );
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