document.write( "Question 242570: A woman is 20 years more than the age of her daughter. In eleven years she will be 3 years less than twice her daughter's age, how old is each now?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #177579 by College Student(505)\"\" \"About 
You can put this solution on YOUR website!
Let daughter = x
\n" ); document.write( "Let mom = x+20
\n" ); document.write( ".
\n" ); document.write( "In 11 years mom will be 3 years less than twice her daughter's age.
\n" ); document.write( "So, in 11 years mom will be (x+20)+11 and her daughter will be x+11, right?
\n" ); document.write( "Therefore, the equation would be: \"%28x%2B20%29%2B11=2%28x%2B11%29-3\"
\n" ); document.write( "Now solve for x to find the daughter's age, then add 20 to find mom's age.
\n" ); document.write( ".
\n" ); document.write( "I'll let you take it from here. :)
\n" ); document.write( "
\n" );