document.write( "Question 242526: Solve the following without using cross multiplication:\r
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document.write( "A motorbike can run for 10 minutes on $1.30 worth of fuel. How long could it run on $0.91 worth of fuel?\r
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document.write( "Please help. Even just some ideas would be great. Thank you. \n" );
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Algebra.Com's Answer #177555 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "You can set up the proportion the same way, just do the division first. Not that it matters much. You still end up doing the same arithmetic.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The only way to solve it without using some form of the manipulations of cross-multiplication is to not use algebra at all. You go find the motorbike that you know can run 10 minutes on $1.30, put $0.91 worth of gas in the tank that you have previously emptied, and then time how long the bike runs.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |