document.write( "Question 242506: A 10% acid solution is to be mixed with a 50% acid solution in order to get 120 ounces of a 20% acid solution. How many ounces of the 10% solution and 50% solution should be mixed? \n" ); document.write( "
Algebra.Com's Answer #177539 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A 10% acid solution is to be mixed with a 50% acid solution in order to get 120 ounces of a 20% acid solution. How many ounces of the 10% solution and 50% solution should be mixed? \n" ); document.write( "------------------------------------ \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.10x + 0.50(120-x) = 0.20*120 \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "10x + 50*120 - 50x = 20*120 \n" ); document.write( "-40x = -30*120 \n" ); document.write( "x = 90 ounces (amount of 10% solution in the mix) \n" ); document.write( "---------------------- \n" ); document.write( "120-x = 30 ounces (amount of 50% solution in the mix) \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |