document.write( "Question 242481: log3 x + log3 (x-24)= 4
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Algebra.Com's Answer #177520 by stanbon(75887)\"\" \"About 
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log3 x + log3 (x-24)= 4
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\n" ); document.write( "log3[x(x-24)] = 4
\n" ); document.write( "x^2-24x = 3^4 = 81
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\n" ); document.write( "x^2 - 24x - 81 = 0
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\n" ); document.write( "x^2 - 27x + 3x - 81 = 0
\n" ); document.write( "x(x-27) + 3(x-27) = 0
\n" ); document.write( "(x-27)(x+3) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 27
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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