document.write( "Question 242477: at maximum speed airplan travel 2460 miles against the wind in 6 hours flying with the wind the plan can travel the same distance in 5 hours \n" ); document.write( "
Algebra.Com's Answer #177494 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! at maximum speed an airplane can travel 2460 miles against the wind in 6 hours flying with the wind the plane can travel the same distance in 5 hours \n" ); document.write( "---------------- \n" ); document.write( "Against the wind DATA: \n" ); document.write( "distance = 2460 miles ; time = 6 hrs. ; rate = 2460/6 = 410 mph \n" ); document.write( "---------------------------- \n" ); document.write( "With the wind DATA: \n" ); document.write( "distance = 2460 miles ; time = 5 hrs. ; rate = 492 mph \n" ); document.write( "---------------------------- \n" ); document.write( "Equations: \n" ); document.write( "p + w = 492 \n" ); document.write( "p - w = 410 \n" ); document.write( "--------------------- \n" ); document.write( "Add: \n" ); document.write( "2p = 902 \n" ); document.write( "p = 451 mph (speed of the plane in still air) \n" ); document.write( "---------------- \n" ); document.write( "Substitute into p+w = 492 to solve for \"w\": \n" ); document.write( "451+w = 492 \n" ); document.write( "w = 41 mph (speed of the wind) \n" ); document.write( "================================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |