document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242411>Question 242411</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kimberly and Andrew use a metal alloy that is 27.32% copper to make jewelry. how many ounces of a 26% alloy must be mixed with a 29% alloy to form 75 ounces of the desired alloy?\r<BR>\n" );
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document.write( "I don't know how to set this one up. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177476 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> : Kimberly and Andrew use a metal alloy that is 27.32% copper to make jewelry.<BR>\n" );
document.write( " how many ounces of a 26% alloy must be mixed with a 29% alloy to form 75 ounces of the desired alloy? <BR>\n" );
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document.write( "Set it up this way.<BR>\n" );
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document.write( "Let x = amt 29% alloy required<BR>\n" );
document.write( "The total is to be 75 oz, therefore<BR>\n" );
document.write( "(75-x) = amt of 26% alloy required<BR>\n" );
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document.write( ".29x + .26(75-x) = .2732(75) </SPAN>\n" );
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