document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242391>Question 242391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Radical 2y-5 = 1 + Radical y-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177430 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177430\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt{2y - 5} = 1 + sqrt{y - 3}\r<BR>\n" );
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document.write( "Isolate the radicals.\r<BR>\n" );
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document.write( "sqrt{2y - 5} - sqrt{y - 3} = 1\r<BR>\n" );
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document.write( "Square both sides.\r<BR>\n" );
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document.write( "[sqrt{2y - 5} - sqrt{y - 3}]^2 = (1)^2\r<BR>\n" );
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document.write( "Can you take it from here?\r<BR>\n" );
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