document.write( "Question 242341: how many liters of pure alcohol must be added to 5 liters of a 15% alcohol solution to make a 25% solution?
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Algebra.Com's Answer #177393 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of pure alcohol needed \n" ); document.write( "Now we know that the amount of pure alcohol added (x) plus the amount of pure alcohol in the 5 liters((0.15)*5) has to equal the amount of pure alcohol in the final mixture ((0.25)*(5+x)). So our equation to solve is: \n" ); document.write( "x+0.15*5=0.25(5+x) get rid of parens and simplify \n" ); document.write( "x+0.75=1.25+0.25x subtract 0.25x and also 0.75 from each side \n" ); document.write( "x-0.25x+0.75-0.75=1.25-0.75+0.25x-0.25x collect like terms \n" ); document.write( "0.75x=0.50 divide each side by 0.75 \n" ); document.write( "x=2/3 liter------------amount of pure alcohol needed \n" ); document.write( "CK \n" ); document.write( "Now we'll deal in fractions \n" ); document.write( "pure alcohol before they are mixed=pure alcohol after they are mixed \n" ); document.write( "2/3 + 3/4 =(1/4)(5+2/3) \n" ); document.write( "8/12 + 9/12=(1/4)(17/3) \n" ); document.write( "17/12 = 17/12\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |