document.write( "Question 242274: Solve 2h+3f=5.25 and h+2f=3.00 \n" ); document.write( "
Algebra.Com's Answer #177374 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "We can solve this a couple different ways. Let's do substitution. To do that let's get the h alone in the second equation.
\n" ); document.write( "2h+3f=5.25
\n" ); document.write( "h+2f=3.00
\n" ); document.write( "It will look like:
\n" ); document.write( "h=3.00-2f Subtract 2f from both sides. Now plug this into the first equation so it looks like this:
\n" ); document.write( "2(3.00-2f)+3f=5.25 Solve for f to get:
\n" ); document.write( "6-4f+3f=5.25 Combine like terms and Subtract 6 from both sides gets us:
\n" ); document.write( "-f=-.75 or
\n" ); document.write( "f=.75 Now plug .75 into either original equation to find h.
\n" ); document.write( "2h+3(.75)=5.25
\n" ); document.write( "2h+2.25=5.25 Subtract 2.25 from both sides to get:
\n" ); document.write( "2h=3 Divide both sides by 2 to get:
\n" ); document.write( "h=1.5 So now we have what h and f are. use these in the equations abouve and it will work out.
\n" ); document.write( "RJ Toftness
\n" ); document.write( "www.math-unlock.com
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