document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242300>Question 242300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the surface area of the following:<BR>\n" );
document.write( "If they are to difficult to answer because the picture is not included just help me out with the correct formulas. Thank you.\r<BR>\n" );
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document.write( "1.Right circular cylinder topped with hemisphere.<BR>\n" );
document.write( "base is 20ft height is 60ft.\r<BR>\n" );
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document.write( "2. Right circular cone topped with hemisphere.<BR>\n" );
document.write( "Height of cone is 8cm and radius of hemisphere is 4cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177372 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. s.a. hemisphere ___ 2 pi r^2<BR>\n" );
document.write( "___ lateral area cylinder ___ 2 pi r h<BR>\n" );
document.write( "___ area - end of cylinder ___ pi r^2\r<BR>\n" );
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document.write( "2. lateral area cone ___ 2 pi r s (s is slant height of cone)<BR>\n" );
document.write( "___ by Pythagoras, s^2 = r^2 + h^2 </SPAN>\n" );
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