document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242198>Question 242198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> square root of (3x+3)+ square root of (x+2)= 5, solve for x.  The answer is 2, need the steps for the answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177365 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177365\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(3x+3)+sqrt(x+2)=5<BR>\n" );
document.write( "sqrt(3x+3)=5-sqrt(x+2)<BR>\n" );
document.write( "3x+3=x+27-10sqrt(x+2) Square each side.<BR>\n" );
document.write( "2x-24=-10sqrt(x+2)<BR>\n" );
document.write( "4x^2-96x+576=100x+200 square each side.<BR>\n" );
document.write( "4x^2-196x+376=0<BR>\n" );
document.write( "4(x^2-49x+94)=0<BR>\n" );
document.write( "(x-47)(x-2)=0<BR>\n" );
document.write( "x=2 is the only answer. x=47 is extraneous.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );