document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242281>Question 242281</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have an isosceles triangle with the top angle given as 3x-48 and then the base of the triangle, with both angles equal and no measure given, but one side of the base of the triangle is extented out with the measurement of 9x. (showing supplement)  But I can not find x with just that information.  Is something missing or how do I go about solving this?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177362 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the supplement of ANY angle of a triangle equals the sum of the other two angles<BR>\n" );
document.write( "___ (because all 3 added together equal 180º)\r<BR>\n" );
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document.write( "9x = 180 - 9x + 3x - 48 </SPAN>\n" );
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