document.write( "Question 242148: at noon, car A started to travel at a uniform speed from town X to town Y which was 60KM away from town X. One and a half hours later, car B started to travel at the same uniform speed as car a from town Y to town X. They passed each other at 3P.M. What distance had they each travelled when they passed each other?
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Algebra.Com's Answer #177313 by ankor@dixie-net.com(22740)\"\" \"About 
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at noon, car A started to travel at a uniform speed from town X to town Y which was 60KM away from town X.
\n" ); document.write( " One and a half hours later, car B started to travel at the same uniform speed as car a from town Y to town X. They passed each other at 3 PM
\n" ); document.write( " What distance had they each traveled when they passed each other?
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\n" ); document.write( "We know when A meets B, their total travel dist will be 60 km
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\n" ); document.write( "Travel time when they met a 3 PM
\n" ); document.write( "Car A travel time = 3 hrs
\n" ); document.write( "Car B travel time = 1.5 hrs
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\n" ); document.write( "Let d = Car A travel distance
\n" ); document.write( "then
\n" ); document.write( "(60-d) = Car B travel distance
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\n" ); document.write( "Write a speed equation Speed = dist/time (Both drive at the same speed)
\n" ); document.write( "\"d%2F3\" = \"%2860-d%29%2F1.5\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "1.5d = 3(60-d)
\n" ); document.write( "1.5d = 180 - 3d
\n" ); document.write( "1.5d + 3d = 180
\n" ); document.write( "4.5d = 180
\n" ); document.write( "d = \"180%2F4.5\"
\n" ); document.write( "d = 40 km traveled by Car A
\n" ); document.write( "and
\n" ); document.write( "60 - 40 = 20 km traveled by Car B
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\n" ); document.write( "Check solution finding the speed of each, they should be equal:
\n" ); document.write( "40/3 = 13\"1%2F3\" kmh
\n" ); document.write( "20/1.5 = 13\"1%2F3\" kmh
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