document.write( "Question 242168: A person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. How many of each coin does the person have \n" ); document.write( "
Algebra.Com's Answer #177286 by stanbon(75887)\"\" \"About 
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A person has quarters and dimes that total $2.80. The number of dimes is 7 more than the number of quarters. How many of each coin does the person have
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity Eq::: d = q + 7
\n" ); document.write( "Value Eq:::::: 10d + 25q = 280 cents
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\n" ); document.write( "Substitute for \"d\" in the and Value Eq. and solve for \"q\":
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\n" ); document.write( "10(q+7) + 25q = 280
\n" ); document.write( "35q = 210
\n" ); document.write( "q = 6 (# of quarters)
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\n" ); document.write( "Substitute into d = q + 7 to get d = 13 (# of dimes)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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