document.write( "Question 242084: Please help me solve the following equation.\r
\n" ); document.write( "\n" ); document.write( "\"+3%2B+sqrt%28+3x-5+%29+=x\"
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Algebra.Com's Answer #177278 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
\"+3%2B+sqrt%28+3x-5+%29+=x\"
\n" ); document.write( "sqrt(3x-5)=x-3 square both sides
\n" ); document.write( "3x-5=(x-3)^2
\n" ); document.write( "3x-5=x^2-6x+9
\n" ); document.write( "x^2-6x-3x+9+5=0
\n" ); document.write( "x^2-9x+14=0
\n" ); document.write( "(x-7)(x-2)=0
\n" ); document.write( "x-7=0
\n" ); document.write( "x=7 ans.
\n" ); document.write( "x-2=0
\n" ); document.write( "x=2 ans.\r
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