document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242106>Question 242106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 5 times the smaller of two numbers is subtracted from twice the larger, the result is 16. If the larger is increased by three times the smaller, the result is 63. Find the larger number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177267 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177267\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write down what you have..use S for smaller and L for larger\r<BR>\n" );
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document.write( "you know that 5S subtracted from 2L is equal to 16\r<BR>\n" );
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document.write( "So: 2L - 5S = 16\r<BR>\n" );
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document.write( "and you know that L + 3S = 63 and you can write this so L = 63-3S\r<BR>\n" );
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document.write( "use substitution:\r<BR>\n" );
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document.write( "2(63-3S) - 5S = 16....solve for S\r<BR>\n" );
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document.write( "Once you have S then plug it into one of the equations and solve for L\r<BR>\n" );
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document.write( "Good Luck </SPAN>\n" );
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