document.write( "Question 242129: The perimeter of a rectangle is 18 feet, and the area of the rectangle is 20 square feet. What is the length of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #177251 by checkley77(12844)\"\" \"About 
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xy=20
\n" ); document.write( "x=20/y
\n" ); document.write( "2x+2y=18 replace x with (20/y) & solve for y.
\n" ); document.write( "2(20/y)+2y=18
\n" ); document.write( "40/y+2y=18
\n" ); document.write( "(40+2y*y)/y=18
\n" ); document.write( "40+2y^2=18y
\n" ); document.write( "2y^2+40=18y
\n" ); document.write( "2y^2-18y+40=0
\n" ); document.write( "2(y^2-9y+20)=0
\n" ); document.write( "(y-5)(y-4)=0
\n" ); document.write( "y-5=0
\n" ); document.write( "y=5 ans.
\n" ); document.write( "y-4=0
\n" ); document.write( "y=4 ans
\n" ); document.write( "x=20/5=4 ans
\n" ); document.write( "x=20/4=5 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "4*5=20
\n" ); document.write( "2*4+2*5=18
\n" ); document.write( "8+10=18
\n" ); document.write( "18=18
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