document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242101>Question 242101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 104. The larger is 1 less than twice the smaller number. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #177247 by </B><A HREF=/tutors/aboutme.mpl?userid=College+Student><B>College Student(505)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=College+Student><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=College+Student><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=177247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let one number = x<BR>\n" );
document.write( "The other number is 1 less than twice the smaller number = 2x-1<BR>\n" );
document.write( "Their sum is 104.<BR>\n" );
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document.write( "Here is your equation: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B2x-1=104 ALIGN=MIDDLE  ALT=\"x%2B2x-1=104\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Solve for x to determine its value and plug it into (2x-1) to find the other value.<BR>\n" );
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document.write( "Remember to check your answers by pluggin the x value in the original equation.  Both sides must equal to each other. </SPAN>\n" );
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